8/(2x^2)=16

Solution for 8/(2x^2)=16 equation:

8/(2x^2)=16

We move all terms to the left:

8/(2x^2)-(16)=0


Domain of the equation: 2x^2!=0

x^2!=0/2

x^2!=√0

x!=0

x∈R


We multiply all the terms by the denominator


-16*2x^2+8=0

Wy multiply elements

-32x^2+8=0

a = -32; b = 0; c = +8;
Δ = b2-4ac
Δ = 02-4·(-32)·8
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-32}{2*-32}=\frac{-32}{-64}
=1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+32}{2*-32}=\frac{32}{-64}
=-1/2
$